How do I check if an element is hidden in jQuery?

Philip Morton Source

It is possible to toggle the visibility of an element, using the functions .hide(), .show() or .toggle().

How would you test if an element is visible or hidden?



answered 10 years ago Mote #1

if ( $(element).css('display') == 'none' || $(element).css("visibility") == "hidden"){
    // element is hidden

Above method does not consider the visibility of the parent. To consider the parent as well, you should use .is(":hidden") or .is(":visible").

For example,

<div id="div1" style="display:none">
  <div id="div2" style="display:block">Div2</div>

The above method will consider div2 visible while :visible not. But the above might be useful in many cases, especially when you need to find if there is any error divs visible in the hidden parent because in such conditions :visible will not work.

answered 10 years ago twernt #2

You can use the hidden selector:

// Matches all elements that are hidden

And the visible selector:

// Matches all elements that are visible

answered 10 years ago Tsvetomir Tsonev #3

Since the question refers to a single element, this code might be more suitable:

// Checks css for display:[none|block], ignores visibility:[true|false]

// The same works with hidden

Same as twernt's suggestion, but applied to a single element; and it matches the algorithm recommended in the jQuery FAQ

answered 9 years ago Simon_Weaver #4

Often when checking if something is visible or not, you are going to go right ahead immediately and do something else with it. jQuery chaining makes this easy.

So if you have a selector and you want to perform some action on it only if is visible or hidden, you can use filter(":visible") or filter(":hidden") followed by chaining it with the action you want to take.

So instead of an if statement, like this:

if ($('#btnUpdate').is(":visible"))
     $('#btnUpdate').animate({ width: "toggle" });   // Hide button

Or more efficient, but even uglier:

var button = $('#btnUpdate');
if (":visible"))
     button.animate({ width: "toggle" });   // Hide button

You can do it all in one line:

$('#btnUpdate').filter(":visible").animate({ width: "toggle" });

answered 8 years ago user574889 #5

From How do I determine the state of a toggled element?

You can determine whether an element is collapsed or not by using the :visible and :hidden selectors.

var isVisible = $('#myDiv').is(':visible');
var isHidden = $('#myDiv').is(':hidden');

If you're simply acting on an element based on its visibility, you can just include :visible or :hidden in the selector expression. For example:

 $('#myDiv:visible').animate({left: '+=200px'}, 'slow');

answered 7 years ago aaronLile #6

None of these answers address what I understand to be the question, which is what I was searching for, "How do I handle items that have visibility: hidden?". Neither :visible nor :hidden will handle this, as they are both looking for display per the documentation. As far as I could determine, there is no selector to handle CSS visibility. Here is how I resolved it (standard jQuery selectors, there may be a more condensed syntax):

$(".item").each(function() {
    if ($(this).css("visibility") == "hidden") {
        // handle non visible state
    } else {
        // handle visible state

answered 7 years ago Abiy #7

This works for me, and I am using show() and hide() to make my div hidden/visible:

if( $(this).css('display') == 'none' ){
    /* your code goes here */
} else {
    /* alternate logic   */

answered 7 years ago Pedro Rainho #8

The :visible selector according to the jQuery documentation:

  • They have a CSS display value of none.
  • They are form elements with type="hidden".
  • Their width and height are explicitly set to 0.
  • An ancestor element is hidden, so the element is not shown on the page.

Elements with visibility: hidden or opacity: 0 are considered to be visible, since they still consume space in the layout.

This is useful in some cases and useless in others, because if you want to check if the element is visible (display != none), ignoring the parents visibility, you will find that doing .css("display") == 'none' is not only faster, but will also return the visibility check correctly.

If you want to check visibility instead of display, you should use: .css("visibility") == "hidden".

Also take into consideration the additional jQuery notes:

Because :visible is a jQuery extension and not part of the CSS specification, queries using :visible cannot take advantage of the performance boost provided by the native DOM querySelectorAll() method. To achieve the best performance when using :visible to select elements, first select the elements using a pure CSS selector, then use .filter(":visible").

Also, if you are concerned about performance, you should check Now you see me… show/hide performance (2010-05-04). And use other methods to show and hide elements.

answered 7 years ago Evgeny Levin #9

I would use CSS class .hide { display: none!important; }.

For hiding/showing, I call .addClass("hide")/.removeClass("hide"). For checking visibility, I use .hasClass("hide").

It's a simple and clear way to check/hide/show elements, if you don't plan to use .toggle() or .animate() methods.

answered 6 years ago think123 #10

Another answer you should put into consideration is if you are hiding an element, you should use jQuery, but instead of actually hiding it, you remove the whole element, but you copy its HTML content and the tag itself into a jQuery variable, and then all you need to do is test if there is such a tag on the screen, using the normal if (!$('#thetagname').length).

answered 6 years ago webvitaly #11

How element visibility and jQuery works;

An element could be hidden with display:none, visibility:hidden or opacity:0. The difference between those methods:

  • display:none hides the element, and it does not take up any space;
  • visibility:hidden hides the element, but it still takes up space in the layout;
  • opacity:0 hides the element as "visibility:hidden", and it still takes up space in the layout; the only difference is that opacity lets one to make an element partly transparent;

    if ($('.target').is(':hidden')) {
    } else {
    if ($('.target').is(':visible')) {
    } else {
    if ($('.target-visibility').css('visibility') == 'hidden') {
        visibility: "visible",
        display: ""
    } else {
        visibility: "hidden",
        display: ""
    if ($('.target-visibility').css('opacity') == "0") {
        opacity: "1",
        display: ""
    } else {
        opacity: "0",
        display: ""

    Useful jQuery toggle methods:

    $('.click').click(function() {
    $('.click').click(function() {
    $('.click').click(function() {

answered 6 years ago ScoRpion #12

One can simply use the hidden or visible attribute, like:


Or you can simplify the same with is as follows.


answered 6 years ago Vaishu #13

ebdiv should be set to style="display:none;". It is works for show and hide:


answered 6 years ago Matt Brock #14

You can also do this using plain JavaScript:

function isRendered(domObj) {
    if ((domObj.nodeType != 1) || (domObj == document.body)) {
        return true;
    if (domObj.currentStyle && domObj.currentStyle["display"] != "none" && domObj.currentStyle["visibility"] != "hidden") {
        return isRendered(domObj.parentNode);
    } else if (window.getComputedStyle) {
        var cs = document.defaultView.getComputedStyle(domObj, null);
        if (cs.getPropertyValue("display") != "none" && cs.getPropertyValue("visibility") != "hidden") {
            return isRendered(domObj.parentNode);
    return false;


  1. Works everywhere

  2. Works for nested elements

  3. Works for CSS and inline styles

  4. Doesn't require a framework

answered 6 years ago Maneesh Kumar #15

This may work:


answered 6 years ago Code Spy #16

$('#clickme').click(function() {
  $('#book').toggle('slow', function() {
    // Animation complete.
    alert($('#book').is(":visible")); //<--- TRUE if Visible False if Hidden
<script src=""></script>
<div id="clickme">
  Click here
<img id="book" src="" alt="" />


Blogger Plug n Play - jQuery Tools and Widgets: How to See if Element is hidden or Visible Using jQuery


JSFiddle - ipsjolly - k4WWj

answered 5 years ago Matthias Wegtun #17

To check if it is not visible I use !:

if ( !$('#book').is(':visible')) {
    alert('#book is not visible')

Or the following is also the sam, saving the jQuery selector in a variable to have better performance when you need it multiple times:

var $book = $('#book')

if(!$':visible')) {
    alert('#book is not visible')

answered 5 years ago Lopsided #18

Use class toggling, not style editing . . .

Using classes designated for "hiding" elements is easy and also one of the most efficient methods. Toggling a class 'hidden' with a Display style of 'none' will perform faster than editing that style directly. I explained some of this pretty thoroughly in Stack Overflow question Turning two elements visible/hidden in the same div.

JavaScript Best Practices and Optimization

Here is a truly enlightening video of a Google Tech Talk by Google front-end engineer Nicholas Zakas:

answered 5 years ago Irfan DANISH #19


$(document).ready(function() {
  if ($("#checkme:hidden").length) {
<script src=""></script>
<div id="checkme" class="product" style="display:none">
  <span class="itemlist"><!-- Shows Results for Fish --></span> Category:Fish
  <br>Product: Salmon Atlantic
  <br>Specie: Salmo salar
  <br>Form: Steaks

answered 5 years ago cssimsek #20

Also here's a ternary conditional expression to check the state of the element and then to toggle it:

$('someElement').on('click', function(){ $('elementToToggle').is(':visible') ? $('elementToToggle').hide('slow') : $('elementToToggle').show('slow'); });

answered 5 years ago Gaurav #21

if($('#postcode_div').is(':visible')) {
    if($('#postcode_text').val()=='') {
    } else {

answered 5 years ago Premshankar Tiwari #22

You need to check both... Display as well as visibility:

if ($(this).css("display") == "none" || $(this).css("visibility") == "hidden") {
    // The element is not visible
} else {
    // The element is visible

If we check for $(this).is(":visible"), jQuery checks for both the things automatically.

answered 5 years ago Andron #23

Because Elements with visibility: hidden or opacity: 0 are considered visible, since they still consume space in the layout (as described for jQuery :visible Selector) - we can check if element is really visible in this way:

function isElementReallyHidden (el) {
    return $(el).is(":hidden") || $(el).css("visibility") == "hidden" || $(el).css('opacity') == 0;

var booElementReallyShowed = !isElementReallyHidden(someEl);
$(someEl).parents().each(function () {
    if (isElementReallyHidden(this)) {
        booElementReallyShowed = false;

answered 4 years ago Aleko #24

After all, none of examples suits me, so I wrote my own.

Tests (no support of Internet Explorer filter:alpha):

a) Check if the document is not hidden

b) Check if an element has zero width / height / opacity or display:none / visibility:hidden in inline styles

c) Check if the center (also because it is faster than testing every pixel / corner) of element is not hidden by other element (and all ancestors, example: overflow:hidden / scroll / one element over enother) or screen edges

d) Check if an element has zero width / height / opacity or display:none / visibility:hidden in computed styles (among all ancestors)

Tested on

Android 4.4 (Native browser/Chrome/Firefox), Firefox (Windows/Mac), Chrome (Windows/Mac), Opera (Windows Presto/Mac Webkit), Internet Explorer (Internet Explorer 5-11 document modes + Internet Explorer 8 on a virtual machine), Safari (Windows/Mac/iOS)

var is_visible = (function () {
    var x = window.pageXOffset ? window.pageXOffset + window.innerWidth - 1 : 0,
        y = window.pageYOffset ? window.pageYOffset + window.innerHeight - 1 : 0,
        relative = !!((!x && !y) || !document.elementFromPoint(x, y));
        function inside(child, parent) {
                if (child === parent) return true;
                child = child.parentNode;
        return false;
    return function (elem) {
        if (
            document.hidden ||
            elem.offsetWidth==0 ||
            elem.offsetHeight==0 ||
  'hidden' ||
  'none' ||
        ) return false;
        var rect = elem.getBoundingClientRect();
        if (relative) {
            if (!inside(document.elementFromPoint(rect.left + elem.offsetWidth/2, + elem.offsetHeight/2),elem)) return false;
        } else if (
            !inside(document.elementFromPoint(rect.left + elem.offsetWidth/2 + window.pageXOffset, + elem.offsetHeight/2 + window.pageYOffset), elem) ||
       + elem.offsetHeight/2 < 0 ||
                rect.left + elem.offsetWidth/2 < 0 ||
                rect.bottom - elem.offsetHeight/2 > (window.innerHeight || document.documentElement.clientHeight) ||
                rect.right - elem.offsetWidth/2 > (window.innerWidth || document.documentElement.clientWidth)
        ) return false;
        if (window.getComputedStyle || elem.currentStyle) {
            var el = elem,
                comp = null;
            while (el) {
                if (el === document) {break;} else if(!el.parentNode) return false;
                comp = window.getComputedStyle ? window.getComputedStyle(el, null) : el.currentStyle;
                if (comp && (comp.visibility=='hidden' || comp.display == 'none' || (typeof comp.opacity !=='undefined' && comp.opacity != 1))) return false;
                el = el.parentNode;
        return true;

How to use:

is_visible(elem) // boolean

answered 4 years ago Kareem #25

.is(":not(':hidden')") /*if shown*/

answered 4 years ago conceptdeluxe #26

When testing an element against :hidden selector in jQuery it should be considered that an absolute positioned element may be recognized as hidden although their child elements are visible.

This seems somewhat counter-intuitive in the first place – though having a closer look at the jQuery documentation gives the relevant information:

Elements can be considered hidden for several reasons: [...] Their width and height are explicitly set to 0. [...]

So this actually makes sense in regards to the box-model and the computed style for the element. Even if width and height are not set explicitly to 0 they may be set implicitly.

Have a look at the following example:

console.log($('.foo').is(':hidden')); // true
console.log($('.bar').is(':hidden')); // false
.foo {
  position: absolute;
  left: 10px;
  top: 10px;
  background: #ff0000;

.bar {
  position: absolute;
  left: 10px;
  top: 10px;
  width: 20px;
  height: 20px;
  background: #0000ff;
<script src=""></script>
<div class="foo">
  <div class="bar"></div>


With jQuery 3 the described behavior will change! Elements will be considered visible if they have any layout boxes, including those of zero width and/or height.

JSFiddle with jQuery 3.0.0-alpha1:

The same JS will then have this output:

console.log($('.foo').is(':hidden')); // false
console.log($('.bar').is(':hidden')); // false

answered 4 years ago pixellabme #27

Simply check visibility by checking for a boolean value, like:

if (this.hidden === false) {
    // Your code

I used this code for each function. Otherwise you can use is(':visible') for checking the visibility of an element.

answered 4 years ago RN Kushwaha #28

But what if the element's CSS is like the following?

    position: absolute;left:-9999;    

So this answer to Stack Overflow question How to check if an element is off-screen should also be considered.

answered 4 years ago V31 #29

A function can be created in order to check for visibility/display attributes in order to gauge whether the element is shown in the UI or not.

function checkUIElementVisible(element) {
    return ((element.css('display') !== 'none') && (element.css('visibility') !== 'hidden'));

Working Fiddle

answered 3 years ago Mathias Stavrou #30

Maybe you can do something like this

$(document).ready(function() {
   var visible = $('#tElement').is(':visible');

   if(visible) {
                    // Code
<script src=""></script>

<input type="text" id="tElement" style="display:block;">Firstname</input>

answered 3 years ago Roman Losev #31

Example of using the visible check for adblocker is activated:

    $("#ablockermsg").text("Please disable adblocker.").show();
<script src=""></script>
<div class="ad-placement" id="ablockercheck"></div>
<div id="ablockermsg" style="display: none"></div>

"ablockercheck" is a ID which adblocker blocks. So checking it if it is visible you are able to detect if adblocker is turned On.

answered 3 years ago Prabhagaran #32


answered 3 years ago Sangeet Shah #33

This is some option to check that tag is visible or not

 // using a pure CSS selector  
   if ($('p:visible')) {  
      alert('Paragraphs are visible (checked using a CSS selector) !');  
   // using jQuery's is() method  
   if ($('p').is(':visible')) {  
      alert('Paragraphs are visible (checked using is() method)!');  
   // using jQuery's filter() method  
   if ($('p').filter(':visible')) {  
      alert('Paragraphs are visible (checked using filter() method)!');  
   // you can use :hidden instead of :visible to reverse the logic and check if an element is hidden  
   // if ($('p:hidden')) {  
   //    do something  
   // };  

answered 3 years ago cbertelegni #34

    // your code..

answered 2 years ago Sahan #35

You can just add a class when it is visible. Add a class, show. Then check for it have a class:


It returns true if you have the show class.

Add CSS like this:

.show{ display: block; }

answered 2 years ago Oriol #36

This is how jQuery internally solves this problem:

jQuery.expr.pseudos.visible = function( elem ) {
    return !!( elem.offsetWidth || elem.offsetHeight || elem.getClientRects().length );

If you don't use jQuery, you can just leverage this code and turn it into your own function:

function isVisible(elem) {
    return !!( elem.offsetWidth || elem.offsetHeight || elem.getClientRects().length );

Which isVisible will return true as long as the element is visible.

answered 2 years ago Abrar Jahin #37

You can use this:


Example code


       if( $('#content').is(':visible') )
          alert("visible"); // Put your code for visibility
<script src=""></script>

<p id="content">This is a Content</p>

<button id="toggle">Toggle Content Visibility</button>
<button id="visibility">Check Visibility</button>

answered 2 years ago lmcDevloper #38

I searched for this, and none of the answers are correct for my case, so I've created a function that will return false if one's eyes can't see the element

  isvisible: function() {
    //  This function call this: $("div").isvisible()
    //  Return true if the element is visible
    //  Return false if the element is not visible for our eyes
    if ( $(this).css('display') == 'none' ){
        console.log("this = " + "display:none");
        return false;
    else if( $(this).css('visibility') == 'hidden' ){
        console.log("this = " + "visibility:hidden");   
        return false;
    else if( $(this).css('opacity') == '0' ){
        console.log("this = " + "opacity:0");
        return false;
        console.log("this = " + "Is Visible");
        return true;

answered 2 years ago No one #39

As hide(), show() and toggle() attaches inline css (display:none or display:block) to element. Similarly, we can easily use ternary operator to check weather element is hidden or visible by checking display css.


  • You also need to check if element css set to visibility: "visible" or visibility: "hidden"
  • Element will be also visible if display property set to inline-block, block, flex.

So we can check for property of element that makes it invisible. So they are display: none and visibility: "hidden";

We can create an object for checking property responsible for hiding element:

var hiddenCssProps = {
display: "none",
visibility: "hidden"

We can check by looping through each key value in object matching if element property for key matches with hidden property value.

var isHidden = false;
for(key in hiddenCssProps) {
  if($('#element').css(key) == hiddenCssProps[key]) {
     isHidden = true;

If you want to check property like element height: 0 or width: 0 or more, you can extend this object and add more property to it and can check.

Thank you @Krzysztof Przygoda for reminding me other display properties.

answered 2 years ago Wolfack #40

You can use the

$( "div:visible" ).click(function() {
  $( this ).css( "background", "yellow" );
$( "button" ).click(function() {
  $( "div:hidden" ).show( "fast" );

API Documentation:

answered 2 years ago Sky Yip #41

I just want to clarify that, in jQuery,

Elements can be considered hidden for several reasons:

  • They have a CSS display value of none.
  • They are form elements with type="hidden".
  • Their width and height are explicitly set to 0.
  • An ancestor element is hidden, so the element is not shown on the page.

Elements with visibility: hidden or opacity: 0 are considered to be visible, since they still consume space in the layout. During animations that hide an element, the element is considered to be visible until the end of the animation.

Source: :hidden Selector | jQuery API Documentation

if($('.element').is(':hidden')) {
  // Do something

answered 2 years ago Arun Karnawat #42

There are quite a few ways to check if an element is visible or hidden in jQuery.

Demo HTML for example reference

<div id="content">Content</div>
<div id="content2" style="display:none">Content2</div>

Use Visibility Filter Selector $('element:hidden') or $('element:visible')

  • $('element:hidden'): Selects all elements that are hidden.

  • $('element:visible'): Selects all elements that are visible.

       $('#content:visible').css('color', '#EEE');


Use is() Filtering

       $('#content').is(":visible").css('color', '#EEE');

    Or checking condition
    if ($('#content').is(":visible")) {
         // Perform action


answered 2 years ago Abdul Aziz Al Basyir #43

There are too many methods to check for hidden elements. This is the best choice (I just recommended you):

Using jQuery, make an element, "display:none", in CSS for hidden.

The point is:


And an example for use:


answered 1 year ago Peter Wone #44

To be fair the question pre-dates this answer. I add it not to criticise the OP but to help anyone still asking this question.

The correct way to determine whether something is visible is to consult your view-model. If you don't know what that means then you are about to embark on a journey of discovery that will make your work a great deal less difficult.

Here's an overview of the model-view-viewmodel architecture (MVVM).

KnockoutJS is a binding library that will let you try this stuff out without learning an entire framework.

And here's some JS and a DIV that may or may not be visible.

<script src=""></script>
var vm = {
  IsDivVisible: ko.observable(true);
vm.toggle = function(data, event) {
  //get current visibility state for the div
  var x = IsDivVisible();
  //set it to the opposite
<div data-bind="visible: IsDivVisible">Peekaboo!</div>
<button data-bind="click: toggle">Toggle the div's visibility</button>

Notice that the toggle function does not consult the DOM to determine the visibility of the div, it consults the view-model.

answered 1 year ago user6119825 #45

$('someElement').on('click', function(){ $('elementToToggle').is(':visible')

answered 1 year ago Alireza #46

Just simply check if that element is visible and it will return a boolean, jQuery hide the elements by adding display none to the element, so if you want to use pure JavaScript, you can still do that, for example:

if (document.getElementById("element").style.display === 'block') { 
  // your element is visible, do whatever you'd like

Also, you can use jQuery as seems the rest of your code using that and you have smaller block of code, something like below in jQuery, do the same track for you:

if ($(element).is(":visible")) { 
    // your element is visible, do whatever you'd like

Also using css method in jQuery can result the same thing:

if ($(element).css('display')==='block') {
    // your element is visible, do whatever you'd like

Also in case of checking for visibility and display, you can do the below:

if ($(this).css("display")==="block"||$(this).css("visibility")==="visible") {
   // your element is visible, do whatever you'd like

answered 1 year ago Antoine Auffray #47

Simply check for the display attribute (or visibility depending on what kind of invisibility you prefer). Example :

if ($('#invisible').css('display') == 'none') {
    // This means the HTML element with ID 'invisible' has its 'display' attribute set to 'none'

answered 12 months ago Sahan #48

You can use a css class when it visible or hidden by toggling the class.

.show{ display :block; }

Set your jQuery toggleClass() or addClass() or removeClass();.

As an example,


The above code will add show css class when the element don't have show and will remove when it has show class.

And when you are checking if it visible or not, You can follow this jQuery code,


Above code will return a boolean (true) when #myID element has our class (show) and false when it don't have the (show) class.

answered 9 months ago Judah rogan #49

You can do this:

isHidden = function(element){
    return ( === "none");

if(isHidden($("element")) == true){
    // something

answered 2 months ago user10145552 #50

Instead of writing an event for every single element, Do this:

  if($(this).css('display') === 'none'){

Also you can use it on the inputs:

  if($(this).attr('type') === 'hidden'){
    $(this).attr('type', 'text');

answered 1 month ago Profesor08 #51

Some times, if you want to check if element is visible on page, depending on visibility of his parrent, you can check if width and height, of element, are equals to 0, both.


$element.width() === 0 && $element.height() === 0


element.clientWidth === 0 && element.clientHeight === 0


element.offsetWidth === 0 && element.offsetHeight === 0

answered 2 weeks ago Muhammad #52

jQuery solution, quite old question but still I fell I can give a bit better answer for those who want to change the button text as well.

    var btn = $(this);
    $("#content").toggle(function () {
      btn.text($(this).css("display") === 'none' ? "Show" : "Hide");
<script src=""></script>

<button id="showHide">Hide</button>
<div id="content">
  <h2>Some content</h2>
  What is Lorem Ipsum? Lorem Ipsum is simply dummy text of the printing and typesetting industry. Lorem Ipsum has been the industry's standard dummy text ever since the 1500s, when an unknown printer took a galley of type and scrambled it to make a type specimen book. It has survived not only five centuries, but also the leap into electronic typesetting, remaining essentially unchanged.

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