How do I read every line of a file in Python and store each line as an element in a list?
I want to read the file line by line and append each line to the end of the list.pythonstringfilereadlines
This will yield an "array" of lines from the file.
lines = tuple(open(filename, 'r'))
This is more explicit than necessary, but does what you want.
with open("file.txt", "r") as ins: array =  for line in ins: array.append(line)
See Input and Ouput:
with open('filename') as f: lines = f.readlines()
or with stripping the newline character:
lines = [line.rstrip('\n') for line in open('filename')]
Editor's note: This answer's original whitespace-stripping command,
line.strip(), as implied by Janus Troelsen's comment, would remove all leading and trailing whitespace, not just the trailing
with open(fname) as f: content = f.readlines() # you may also want to remove whitespace characters like `\n` at the end of each line content = [x.strip() for x in content]
I'm guessing that you meant
list and not array.
Another option is
numpy.genfromtxt, for example:
import numpy as np data = np.genfromtxt("yourfile.dat",delimiter="\n")
This will make
data a NumPy array with as many rows as are in your file.
This should encapsulate the open command.
array =  with open("file.txt", "r") as f: for line in f: array.append(line)
If you'd like to read a file from the command line or from stdin, you can also use the
# reader.py import fileinput content =  for line in fileinput.input(): content.append(line.strip()) fileinput.close()
Pass files to it like so:
$ python reader.py textfile.txt
Read more here: http://docs.python.org/2/library/fileinput.html
f = open("your_file.txt",'r') out = f.readlines() # will append in the list out
Now variable out is a list (array) of what you want. You could either do:
for line in out: print line
for line in f: print line
you'll get the same results.
If you want the
with open(fname) as f: content = f.readlines()
If you do not want
with open(fname) as f: content = f.read().splitlines()
Here's one more option by using list comprehensions on files;
lines = [line.rstrip() for line in open('file.txt')]
This should be more efficient way as the most of the work is done inside the Python interpreter.
lines = list(open("dict.lst", "r")) linesSanitized = map(lambda each:each.strip("\n"), lines) print linesSanitized
Clean and Pythonic Way of Reading the Lines of a File Into a List
First and foremost, you should focus on opening your file and reading its contents in an efficient and pythonic way. Here is an example of the way I personally DO NOT prefer:
infile = open('my_file.txt', 'r') # Open the file for reading. data = infile.read() # Read the contents of the file. infile.close() # Close the file since we're done using it.
Instead, I prefer the below method of opening files for both reading and writing as it is very clean, and does not require an extra step of closing the file once you are done using it. In the statement below, we're opening the file for reading, and assigning it to the variable 'infile.' Once the code within this statement has finished running, the file will be automatically closed.
# Open the file for reading. with open('my_file.txt', 'r') as infile: data = infile.read() # Read the contents of the file into memory.
Now we need to focus on bringing this data into a Python List because they are iterable, efficient, and flexible. In your case, the desired goal is to bring each line of the text file into a separate element. To accomplish this, we will use the splitlines() method as follows:
# Return a list of the lines, breaking at line boundaries. my_list = data.splitlines()
The Final Product:
# Open the file for reading. with open('my_file.txt', 'r') as infile: data = infile.read() # Read the contents of the file into memory. # Return a list of the lines, breaking at line boundaries. my_list = data.splitlines()
Testing Our Code:
A fost odatã ca-n povesti, A fost ca niciodatã, Din rude mãri împãrãtesti, O prea frumoasã fatã.
print my_list # Print the list. # Print each line in the list. for line in my_list: print line # Print the fourth element in this list. print my_list
['A fost odat\xc3\xa3 ca-n povesti,', 'A fost ca niciodat\xc3\xa3,', 'Din rude m\xc3\xa3ri \xc3\xaemp\xc3\xa3r\xc3\xa3testi,', 'O prea frumoas\xc3\xa3 fat\xc3\xa3.'] A fost odatã ca-n povesti, A fost ca niciodatã, Din rude mãri împãrãtesti, O prea frumoasã fatã. O prea frumoasã fatã.
The simplest way to do it
A simple way is to:
In one line, that would give:
lines = open('C:/path/file.txt').read().splitlines()
with open(fname) as fo: data=fo.read().replace('\n', ' ').replace (',', ' ')
This should answer your question. The replace function will act as delimiter to strip the file.
If you don't care about closing the file, this one-liner works:
lines = open('file.txt').read().split("\n")
The traditional way:
fp = open('file.txt') # Open file on read mode lines = fp.read().split("\n") # Create a list containing all lines fp.close() # Close file
with open('file.txt') as fp: lines = fp.read().split("\n")
You could also use the loadtxt command in NumPy. This checks for fewer conditions than genfromtxt, so it may be faster.
import numpy data = numpy.loadtxt(filename, delimiter="\n")
textFile = open("E:\Values.txt","r") textFileLines = textFile.readlines()
"textFileLines" is the array you wanted
You could simply do the following, as has been suggested:
with open('/your/path/file') as f: my_lines = f.readlines()
Note that this approach has 2 downsides:
1) You store all the lines in memory. In the general case, this is a very bad idea. The file could be very large, and you could run out of memory. Even if it's not large, it is simply a waste of memory.
2) This does not allow processing of each line as you read them. So if you process your lines after this, it is not efficient (requires two passes rather than one).
A better approach for the general case would be the following:
with open('/your/path/file') as f: for line in f: process(line)
Where you define your process function any way you want. For example:
def process(line): if 'save the world' in line.lower(): superman.save_the_world()
(The implementation of the
Superman class is left as an exercise for you).
This will work nicely for any file size and you go through your file in just 1 pass. This is typically how generic parsers will work.
To my knowledge Python doesn't have a native array data structure. But it does support the list data structure which is much simpler to use than an array.
array =  #declaring a list with name '**array**' with open(PATH,'r') as reader : for line in reader : array.append(line)
A real easy way:
with open(file) as g: stuff = g.readlines()
If you want to make it a fully-fledged program, type this in:
file = raw_input ("Enter EXACT file name: ") with open(file) as g: stuff = g.readlines() print (stuff) exit = raw_input("Press enter when you are done.")
For some reason, it doesn't read .py files properly.
import pandas as pd data = pd.read_csv(filename) # You can also add parameters such as header, sep, etc. array = data.values
data is a dataframe type, and uses values to get ndarray. You can also get a list by using
fp = open("filename") content = fp.read(); lines = content.split("\n")
Just use the splitlines() functions. Here is an example.
inp = "file.txt" data = open(inp) dat = data.read() lst = dat.splitlines() print lst # print(lst) # for python 3
In the output you will have the list of lines.
I'd do it like this.
lines =  with open("myfile.txt") as f: for line in f: lines.append(line)
If you want to are faced with a very large / huge file and want to read faster (imagine you are in a Topcoder/Hackerrank coding competition), you might read a considerably bigger chunk of lines into a memory buffer at one time, rather than just iterate line by line at file level.
buffersize = 2**16 with open(path) as f: while True: lines_buffer = f.readlines(buffersize) if not lines_buffer: break for line in lines_buffer: process(line)
Data into list
Assume that we have a text file with our data like in the following lines:
line 1 line 2 line 3
pythonand in the interpreter write:
>>> with open("myfile.txt", encoding="utf-8") as file: ... x = [l.strip() for l in file] >>> x ['line 1','line 2','line 3']
x =  with open("myfile.txt") as file: for l in file: x.append(l.strip())
>>> x = open("myfile.txt").read().splitlines() >>> x ['line 1', 'line 2', 'line 3']
>>> y = [x.rstrip() for x in open("my_file.txt")] >>> y ['line 1','line 2','line 3']
You can just open your file for reading using:
file1 = open("filename","r") # And for reading use lines = file1.readlines() file1.close()
lines will contain all your lines as individual elements, and you can call a specific element using
lines["linenumber-1"] as Python starts its counting from 0.
You can easily do it by the following piece of code:
lines = open(filePath).readlines()
#!/bin/python3 import os import sys abspath = os.path.abspath(__file__) dname = os.path.dirname(abspath) filename = dname + sys.argv arr = open(filename).read().split("\n") print(arr)
python3 somefile.py input_file_name.txt
#!/usr/bin/env python3 # -*- coding: utf-8 -*- # Define data lines = [' A first string ', 'A Unicode sample: €', 'German: äöüß'] # Write text file with open('file.txt', 'w') as fp: fp.write('\n'.join(lines)) # Read text file with open('file.txt', 'r') as fp: read_lines = fp.readlines() read_lines = [line.rstrip('\n') for line in read_lines] print(lines == read_lines)
Things to notice:
withis a so-called context manager. It makes sure that the opened file is closed again.
.rstrip()will fail to reproduce the
linesas they also strip the white space.
For your application, the following might be important:
See also: Comparison of data serialization formats
In case you are rather looking for a way to make configuration files, you might want to read my short article Configuration files in Python.
To read a file into a list you need to do three things:
Fortunately Python makes it very easy to do these things so the shortest way to read a file into a list is:
lst = list(open(filename))
However I'll add some more explanation.
I assume that you want to open a specific file and you don't deal directly with a file-handle (or a file-like-handle). The most commonly used function to open a file in Python is
open, it takes one mandatory argument and two optional ones in Python 2.7:
The filename should be a string that represents the path to the file. For example:
open('afile') # opens the file named afile in the current working directory open('adir/afile') # relative path (relative to the current working directory) open('C:/users/aname/afile') # absolute path (windows) open('/usr/local/afile') # absolute path (linux)
Note that the file extension needs to be specified. This is especially important for Windows users because file extensions like
.doc, etc. are hidden by default when viewed in the explorer.
The second argument is the
r by default which means "read-only". That's exactly what you need in your case.
But in case you actually want to create a file and/or write to a file you'll need a different argument here. There is an excellent answer if you want an overview.
For reading a file you can omit the
mode or pass it in explicitly:
open(filename) open(filename, 'r')
Both will open the file in read-only mode. In case you want to read in a binary file on Windows you need to use the mode
On other platforms the
'b' (binary mode) is simply ignored.
Now that I've shown how to
open the file, let's talk about the fact that you always need to
close it again. Otherwise it will keep an open file-handle to the file until the process exits (or Python garbages the file-handle).
While you could use:
f = open(filename) # ... do stuff with f f.close()
That will fail to close the file when something between
close throws an exception. You could avoid that by using a
f = open(filename) # nothing in between! try: # do stuff with f finally: f.close()
However Python provides context managers that have a prettier syntax (but for
open it's almost identical to the
with open(filename) as f: # do stuff with f # The file is always closed after the with-scope ends.
The last approach is the recommended approach to open a file in Python!
Okay, you've opened the file, now how to read it?
open function returns a
file object and it supports Pythons iteration protocol. Each iteration will give you a line:
with open(filename) as f: for line in f: print(line)
This will print each line of the file. Note however that each line will contain a newline character
\n at the end (you might want to check if your Python is built with universal newlines support - otherwise you could also have
\r\n on Windows or
\r on Mac as newlines). If you don't want that you can could simply remove the last character (or the last two characters on Windows):
with open(filename) as f: for line in f: print(line[:-1])
But the last line doesn't necessarily has a trailing newline, so one shouldn't use that. One could check if it ends with a trailing newline and if so remove it:
with open(filename) as f: for line in f: if line.endswith('\n'): line = line[:-1] print(line)
But you could simply remove all whitespaces (including the
\n character) from the end of the string, this will also remove all other trailing whitespaces so you have to be careful if these are important:
with open(filename) as f: for line in f: print(f.rstrip())
However if the lines end with
\r\n (Windows "newlines") that
.rstrip() will also take care of the
Now that you know how to open the file and read it, it's time to store the contents in a list. The simplest option would be to use the
with open(filename) as f: lst = list(f)
In case you want to strip the trailing newlines you could use a list comprehension instead:
with open(filename) as f: lst = [line.rstrip() for line in f]
Or even simpler: The
.readlines() method of the
file object by default returns a
list of the lines:
with open(filename) as f: lst = f.readlines()
This will also include the trailing newline characters, if you don't want them I would recommend the
[line.rstrip() for line in f] approach because it avoids keeping two lists containing all the lines in memory.
There's an additional option to get the desired output, however it's rather "suboptimal":
read the complete file in a string and then split on newlines:
with open(filename) as f: lst = f.read().split('\n')
with open(filename) as f: lst = f.read().splitlines()
These take care of the trailing newlines automatically because the
split character isn't included. However they are not ideal because you keep the file as string and as a list of lines in memory!
with open(...) as fwhen opening files because you don't need to take care of closing the file yourself and it closes the file even if some exception happens.
fileobjects support the iteration protocol so reading a file line-by-line is as simple as
for line in the_file_object:.
readlines()but if you want to process the lines before storing them in the list I would recommend a simple list-comprehension.
I like to use the following. Reading the lines immediately.
contents =  for line in open(filepath, 'r').readlines(): contents.append(line.strip())
Or using list comprehension:
contents = [line.strip() for line in open(filepath, 'r').readlines()]
Introduced in Python 3.4,
pathlib has a really convenient method for reading in text from files, as follows:
from pathlib import Path p = Path('my_text_file') lines = p.read_text().splitlines()
splitlines call is what turns it from a string containing the whole contents of the file to a list of lines in the file).
pathlib has a lot of handy conveniences in it.
read_text is nice and concise, and you don't have to worry about opening and closing the file. If all you need to do with the file is read it all in in one go, it's a good choice.
filename, handling the file from a
Path(filename) object, or directly with
open(filename) as f, do one of the following:
with path.open() as f, call
list.appendeach line one at a time
fto a bound
fin a list comprehension
I explain the use-case for each below.
In Python, how do I read a file line-by-line?
This is an excellent question. First, let's create some sample data:
from pathlib import Path Path('filename').write_text('foo\nbar\nbaz')
File objects are lazy iterators, so just iterate over it.
filename = 'filename' with open(filename) as f: for line in f: line # do something with the line
Alternatively, if you have multiple files, use
fileinput.input, another lazy iterator. With just one file:
import fileinput for line in fileinput.input(filename): line # process the line
or for multiple files, pass it a list of filenames:
for line in fileinput.input([filename]*2): line # process the line
fileinput.input above both are/return lazy iterators.
You can only use an iterator one time, so to provide functional code while avoiding verbosity I'll use the slightly more terse
fileinput.input(filename) where apropos from here.
In Python, how do I read a file line-by-line into a list?
Ah but you want it in a list for some reason? I'd avoid that if possible. But if you insist... just pass the result of
Another direct answer is to call
f.readlines, which returns the contents of the file (up to an optional
hint number of characters, so you could break this up into multiple lists that way).
You can get to this file object two ways. One way is to pass the filename to the
filename = 'filename' with open(filename) as f: f.readlines()
or using the new Path object from the
pathlib module (which I have become quite fond of, and will use from here on):
from pathlib import Path path = Path(filename) with path.open() as f: f.readlines()
list will also consume the file iterator and return a list - a quite direct method as well:
with path.open() as f: list(f)
If you don't mind reading the entire text into memory as a single string before splitting it, you can do this as a one-liner with the
Path object and the
splitlines() string method. By default,
splitlines removes the newlines:
If you want to keep the newlines, pass
I want to read the file line by line and append each line to the end of the list.
Now this is a bit silly to ask for, given that we've demonstrated the end result easily with several methods. But you might need to filter or operate on the lines as you make your list, so let's humor this request.
list.append would allow you to filter or operate on each line before you append it:
line_list =  for line in fileinput.input(filename): line_list.append(line) line_list
list.extend would be a bit more direct, and perhaps useful if you have a preexisting list:
line_list =  line_list.extend(fileinput.input(filename)) line_list
Or more idiomatically, we could instead use a list comprehension, and map and filter inside it if desirable:
[line for line in fileinput.input(filename)]
Or even more directly, to close the circle, just pass it to list to create a new list directly without operating on the lines:
You've seen many ways to get lines from a file into a list, but I'd recommend you avoid materializing large quantities of data into a list and instead use Python's lazy iteration to process the data if possible.
That is, prefer
with path.open() as f.
file into a list:
file = open('C:\Data\TempPlayer.txt','r') lines = list(file) for line in lines: