For a code question: What it wants is for you to make a for loop that will run down the length of the array it provides. We're going to keep track of where we are in the array with our counter variable. At the end, we should have the sum of all the numbers in that array.

I don't understand why my 2nd loop cannot iterate over the whole array, also how do I check the sum, would that just be printing the sum?

```
let numbers = [2,8,1,16,4,3,9]
var sum = 0
var counter = 0
while sum < numbers.count {
print(numbers[sum])
sum += 1
}
while counter < numbers.count {
sum = sum + numbers[counter]
print(numbers[counter])
counter += 1
}
```

arraysswift
answered 2 years ago Westside #1

If all you want is the sum of all the numbers in the array then you can do this...

```
let numbers = [2,8,1,16,4,3,9]
var sum = 0
for number in numbers {
sum += number
}
print (sum)
```

or even easier...

```
sum = numbers.reduce(0, combine: +)
```

answered 2 years ago harshitgupta #2

Strictly following the question statement, I would say the following code will be better option

```
let numbers = [2, 8, 1, 16, 4, 3, 9]
var sum = 0
for counter in 0 ..< numbers.count {
sum += numbers[counter]
print("Counter: \(counter) Sum: \(sum)")
}
```