I aim to write a class who can be used to calculate all the properties of a device.

```
import numpy as np
class pythagoras:
def __init__(self, a=None, b=None, c=None):
self.a = a
self.b = b
self.c = c
if(a == None):
assert(b != None)
assert(c != None)
self.a = np.sqrt(c**2 - b**2)
elif(b == None):
assert(a != None)
assert(c != None)
self.b = np.sqrt(c**2 - a**2)
elif(c == None):
assert(a != None)
assert(b != None)
self.c = np.sqrt(a**2 + b**2)
else:
assert (a**2 + b**2 == c**2), "The values are incompatible."
example1 = pythagoras(a=3, b=4)
print(example.c)
# 5
example2 = pythagoras(a=3, c=5)
print(example2.b)
# 4
example3 = pythagoras(b=4, c=5)
print(example3.a)
# 3
```

So my question is about simplifying this example: Is there a simpler way to implement this kind of problem? For more complex examples it gets quickly rather complex and unmanageable.

The final goal is to have a class with all device properties such as:

```
class crystal:
absorption
refractive_index
transmission
reflection
heat_conductivity
heat_resistance
```

Here one can imagine that these properties depend on each other and according to my knowledge of properties, I can infer the rest of the properties.

I am graceful for any remarks about writing better code. Even though I learned and read literature about object-oriented coding, I am inexperienced in writing such.

pythonpython-3.xclass answered 6 months ago Games Brainiac #1

I think this is rather easy to calculate once you use the `@property`

decorator. Let me show you an example.

import math

```
class Pythagoras(object):
def __init__(self, a=None, b=None, c=None):
self._a = a
self._b = b
self._c = c
count = 0
if self._a is None:
count += 1
if self._b is None:
count += 1
if self._c is None:
count += 1
if count > 1:
raise Exception("More than one of the values are None.")
@property
def a(self):
if self._a is None:
return math.sqrt(self.c**2 - self.b**2)
else:
return self._a
@property
def b(self):
if self._b is None:
return math.sqrt(self.c**2 - self.a**2)
else:
return self._b
@property
def c(self):
if self._c is None:
return math.sqrt(self.a**2 + self.b**2)
else:
return self._c
```

Working behavior:

```
>>> from temp import Pythagoras
>>> p = Pythagoras(a=10, b=20)
>>> p.c
22.360679774997898
```

Edit: Updated the code to make sure that it was working.

answered 6 months ago Cezary.Sz #2

Try this:

```
import pandas as pd
class Pyth():
def __init__(self, a=np.NaN, b=np.NaN, c=np.NaN):
df = pd.DataFrame({
'sides': [a,b,c],
'equation':[np.sqrt(c**2 - b**2), np.sqrt(c**2 - a**2), np.sqrt(a**2 + b**2)]
})
df.loc[df.sides.isnull(), 'sides'] = df[df.sides.isnull()]['equation']
self.a = df.sides[0]
self.b = df.sides[1]
self.c = df.sides[2]
```

Test result:

```
test = Pyth(a=3,b=4)
test.c
Out[217]:
5.0
In [218]:
test.b
Out[218]:
4.0
In [219]:
test.a
Out[219]:
3.0
```