Scrape table through iteration only after data loads with delay using Python?

Ach Source

I am trying to scrape data using python (Requests and BeautifulSoup4 libraries along with Selenium)

When I tried to get some data out of website where the data loads after some delay, it returns an empty value. I understand that for this task i have to use WebDriverWait.

import requests
from bs4 import BeautifulSoup
# selenium imports
from selenium import webdriver
from selenium.webdriver.common.keys import Keys
from import Select
from import WebDriverWait
from import By
from import expected_conditions as EC
from import WebDriverWait
from selenium.common.exceptions import TimeoutException

# Initialize a Chrome webdriver
driver = webdriver.Chrome()

# Grab the web page

# use
# that we imported above to grab the Select element called 
# lmStatType, then select the first value

# We will use .find_element_by_name here because we know the name
dropdown = Select(driver.find_element_by_name("lmStatType"))

# select the year 2560
dropdown = Select(driver.find_element_by_name("lmYear"))

# Now we can grab the search button and click it
search_button = driver.find_elements_by_xpath("//*[contains(text(), 'ตกลง')]"[0]

# we just look at .page_source of the driver

# We can feed that into Beautiful Soup
doc = BeautifulSoup(driver.page_source, "html.parser")

# It's a tricky table, also tried with class names
rows = doc.find('table', id='datatable')
print(rows) # returns empty

In the above example i haven't used the tried options with selenium webdriver wait & timeout related statements for understanding it step-by-step, even though i have tried several workarounds.

Also, just tried grabbing the district level data separately like (but can't figure out the exact class/id)

url = 'http://'
res = requests.get(url)
soup = BeautifulSoup(res.text,"lxml")
for tr in soup.find(class_="display").find_all("tr"):
    data = [item.get_text(strip=True) for item in tr.find_all(["th","td"])]

Any help is appreciated. Thanks in advance. My apology, if this is a duplicate question.



answered 3 months ago jlaur #1

As I stated in a comment the html actually gives you the endpoint where it gets that data. From the on it's actually quite easy getting the data using requests.

In your html as reads: "sAjaxSource": "../datasource/showStatProvince.php?statType=1&year=60". This is the endpoint the site uses. So you just need to go one level back in the sites url-structure and use "/datasource/...." instead

Take look:

import requests
from bs4 import BeautifulSoup
import re

url = ""

r = requests.get(url)
# endpoint returns json
data = r.json()
aaData = data['aaData']

# this base url for viewing the details for each hit
view_url = ""

# the first line in the dataset is actually html
# we convert this to plain text
html_header = aaData[0]
html_header_stripped = [BeautifulSoup(e, "html.parser").get_text() for e in html_header]

# and the insert this html_header_stripped in the aaData-list
aaData[0] = html_header_stripped
for rcode, region_html,male,female, total, home in aaData:
    # first element is "<font color='red'><b>กรุงเทพมหานคร</b></font>"
    # secound is "<a href=javascript:openWindow('?rcode=1001&statType=1&year=60')>ท้องถิ่นเขตพระนคร</a>"
    # we need to extract the link that opens in new window to be able to iterate further
    soup = BeautifulSoup(region_html, "html.parser")
    region = soup.get_text()
        link_element = soup.find('a').get('href')
        rel_link ="\('(.+)'\)", link_element).group(1)
        abs_link = view_url + rel_link
        abs_link = None

    print("{};{};{};{};{};{};{}".format(rcode, region, abs_link,male,female,total,home))

Here I'm printing the results, but say you wanted to follow the links and grab that data, you could store the results in a list of dicts and iterate over this subsequently or do it inside the for loop.

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